Logic Problem Solution:
Puzzles for Dad
From the introduction, no two jigsaw puzzles have the same number of
pieces; and, from clue 1, the puzzle with the fewest pieces has 500
and that with the most 2,000. By clue 2, Cheryl's jigsaw has 1,000
more pieces than "Campaign Buttons"; while by clue 4, Chandra's puzzle
has 1,000 more pieces than "American Beauties." These must be four
different Chizzlethwaite children; otherwise, if Cheryl had bought
"American Beauties" or Chandra had bought "Campaign Buttons," the
three puzzles between clues 2 and 4 would have 500, 1,500, and 2,500
piecesno (1). Chandra didn't buy "Fish, Fish, and More Fish" (7),
so Cheryl did or the child who bought that puzzle would be the fifth
to the four in clues 2 and 4. If the child who bought "Fish ... "
were the fifth Chizzlethwaite daughter, then by clue 6, Chelsea would
have bought "American Beauties." By clue 3, the "Fish ..." jigsaw
doesn't have the 500 pieces. If Chelsea had purchased the 500piece
puzzle, Chandra's would have had 1,500 pieces (4) and "Fish ..." 1,000
(3). Then Cheryl's would have had 2,000 (1) and "Campaign Buttons"
1,000 (2)but two would have the same number and conflict with the
introduction. If "Campaign Buttons" had 500 pieces and Cheryl's then
1,000 (2), if either Chandra's (4) or the "Fish ..." puzzle (3) had
the 2,000 pieces, Chelsea's would have 1,000but then both Chandra's
and the "Fish ..." puzzle would have 2,000 pieces. So, the child
who bought "Fish, Fish, and More Fish" is Cheryl. Then Chelsea is
the fifth child or bought "American Beauties" (6). If the latter were
the case, if Chelsea's choice had the 500 pieces, then Cheryl's would
have had 1,000 (3) and "Campaign Buttons" would have 0 (2)no. If
Chelsea had bought "American Beauties" and "Campaign Buttons" were the
jigsaw of 500 pieces, Cheryl's would have 1,500 (2), Chelsea's 750
(3), and Chandra's 1,750 (4), and the fifth child's would have the
2,000 (1). But there is no way for clue 5 to work given these numbers.
If Chelsea had bought "American Beauties" and the fifth puzzle were the
jigsaw of 500 pieces, then either Cheryl or Chandra would have got her
dad the 2,000piece puzzle. In either case, Chelsea's would have
been a 1,000piece jigsaw (3, 4)but then both Cheryl (3) and Chandra
(4) would have bought puzzles of the same 2,000piece size. Therefore,
Chelsea must be the fifth child to the four in clues 2 and 4. Chelsea
doesn't have the 500piece puzzle, or "Campaign Buttons" would have 0
pieces (3, 2). If "American Beauties" had the fewest pieces, Chandra's
would have 1,500 (4). Then Cheryl's would be the 2,000piece jigsaw
but both "Campaign Buttons" (2) and Chelsea's puzzle (3) would have
1,000, contradicting the introduction. Therefore, "Campaign Buttons"
is a 500piece jigsaw puzzle, with Cheryl's having 1,500 pieces (2)
and Chelsea's thus 750 (3). Chandra's jigsaw is the 2,000piece one,
and "American Beauties" has 1,000 pieces (4). By clue 5, China bought
"American Beauties" for her dad. By elimination, Charlotte got him
"Campaign Buttons." Chelsea picked "Hall of Mirrors" and Chandra
"M & M's" (6). In sum, the girls bought Father's day puzzles for their
dad as follows:
 Chandra, "M & M's," 2,000
 Cheryl, "Fish, Fish, and More Fish," 1,500
 China, "American Beauties," 1,000
 Chelsea, "Hall of Mirrors," 750
 Charlotte, "Campaign Buttons," 500

