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Logic Puzzle # 136 Logic Problems Help



Logic Problem Solution:
Letter Cubes

According to the introduction, each of the 24 faces of the Letter Cubes has a different letter on it. Given the word MOCK, we arbitrarily assign M to cube 1, O to cube 2, C to cube 3, and K to cube 4. From the word CONE, E cannot be on cube 2 or 3; and from the word MARE, E cannot be on cube 1 with M. E is on a face of cube 4. Then from CONE, N is on cube 1 with M. T isn't on cube 4 with E (STEW), nor on cube 1 or 2 (TONY); T is on cube 3. Then Y is on cube 4 (TONY). From MARE, A and R are on cubes 2 and 3 or vice versa. Then W must be on cube 1 or cube 4 (WARD). W isn't on 4 (STEW) and must be on 1. S is on 2 (STEW) and D on 4 (MARE, WARD). From VICE, V and I must be on cubes 1 and 2 or vice versa. However, from DISH, I cannot be on cube 2 with S. So, I in VICE is on cube 1 and V on 2; and H in DISH is on cube 3. From CLOG, L and G are on cubes 1 and 4 or vice versa. From CLIP, L can't be on cube 1 with I; L is on 4 and G in CLOG on 1. P is on cube 2 (CLIP). By QUIP, U isn't on cube 1 with I or cube 2 with P. From FURL, then, U isn't on cube 4 and must be on cube 3--with A; R (MARE) is on cube 2. Then F is the sixth letter on cube 1 (FURL), and Q is the sixth letter on cube 4 (QUIP). From FAZE, Z is the sixth letter on cube 2. By elimination, B is on cube 3. In sum, the faces on the four cubes are

  • A-B-C-H-T-U
  • D-E-K-L-Q-Y
  • F-G-I-M-N-W
  • O-P-R-S-V-Z



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